計數型量具研究(長期方法)
1)在制程變化范圍內選擇8個待測物
2)每個待測物用量具測量20次,紀錄每個待測物合格次數a
3)最小待測物的a=0,最大待測物的a=20
4)其它6個待測物的a介于1到19之間,如果不符,選取額外測量點.
5)計算各待測物的接收概率Pa
6)繪制Pa正態概率圖,計算再現性R
計數型量具研究(長期方法)
Pa=(a+0.5)/m 當a/m<0.5, a&sup1;0
Pa=(a-0.5)/m 當a/m>0.5, a&sup1;20
Pa=0.5 當a/m=0.5
偏倚Bias=XT(Pa=0.5)-下限
再現性R=/1.08
t=(31.1*Bias)/R 當t＞2.093時,偏倚明顯偏离零

在学习minitab14.1：stat>quanlity tools>gage study>attribute gage study(analytic method)时，帮助文件也看了，但一直没有弄明白，今天在网上找到一个关于計數型量具研究(長期方法)的培训资料，明白了一点，但还是存在几个疑问，请各高手不吝赐教！
疑问一、作此测试时对部品有何要求
疑问二、如何理解：3)最小待測物的a=0,最大待測物的a=20；4)其它6個待測物的a介于1到19之間,如果不符,選取額外測量點.这两点！

You must have at least eight parts to conduct an attribute gage study. The smallest part must have zero acceptances, and the largest part must have the maximum number of possible acceptances. For the AIAG method for testing bias, exactly six parts must be greater than zero number of acceptances and less than 20--the maximum number of acceptances allowed in the AIAG situation. For the regression method, you may have more than six parts between the two extreme reference values.

If you specify the lower tolerance limit, the part with the lowest reference value must have 0 acceptances and the part with the highest reference must have the maximum number of possible acceptances. For the lower limit, as the reference values increase, the number of acceptances increases. If you specify the upper tolerance limit, the part with the lowest reference value must have the maximum number of possible acceptances and the part with the highest reference value must have 0 acceptances. For the upper limit, as the reference values increase, the number of acceptances decrease.

You can enter the number of trials as a constant or a column of data. When the number of trials is not identical for all parts, you must enter a column containing the number of trials for each part.

The number of trials for each part must be greater than or equal to 15. If you use the AIAG method (default) to test the bias of the gage, you must have exactly 20 trials per part.

Minitab accepts either summarized or raw data for attribute gage studies.

Summarized Data

Part Number


Reference


Acceptances

1
1.35
0

2
1.40
3

3
1.45
8

4
1.50
13

5
1.55
15

6
1.60
18

7
1.65
19

8
1.70
20

Structure summarized data so that each row contains the part name or number, reference value, and summarized count. Parts can be text or numbers. Reference values and counts must be numeric



Raw Data

Part Number


Reference


Response

1
1.35
Reject

1
1.35
Reject

1
1.35
Reject

1
1.35
Reject

...
...
...

8
1.70
Accept

8
1.70
Accept

8
1.70
Accept

8
1.70
Accept

Structure raw data so that each row contains the part name or number, reference value, and binary response. Parts and responses can be text or numbers. Reference values must be numeric.

帮助文件上说,AIAG方法,必须有8个部品,最小的部品接受值必须为0,最大的部品接受值为20,其它6个部品接受值在0-20之间,如果是回归方法,必须有6个以上的部品接受值在现从极值(接受极值)之间.
如果规定下限,部品参考值和接受值均按小到大排列,旭呆规定上限部吕参考值按小到大排列,接受值按大到小排列

AIAG测试为20次,回归方法测试必须大于等于15次