Minitab计算G R&R问题?
用Minitab计算一组数据(10、3、3)得到的结果如下:
Gage R&R Study - ANOVA Method
Two-Way ANOVA Table With Interaction
Source DF SS MS F P
Sample 9 2208.84 245.426 34.86 0.000
Operator 2 0.83 0.417 0.06 0.943
Sample * Operator 18 126.72 7.040 1439.99 0.000
Repeatability 60 0.29 0.005
Total 89 2336.68
Gage R&R
%Contribution
Source VarComp (of VarComp)
Total Gage R&R 2.3499 8.15
Repeatability 0.0049 0.02
Reproducibility 2.3450 8.13
Operator 0.0000 0.00
Operator*Sample 2.3450 8.13
Part-To-Part 26.4874 91.85
Total Variation 28.8373 100.00
Study Var %Study Var
Source StdDev (SD) (6 * SD) (%SV)
Total Gage R&R 1.53294 9.1977 28.55
Repeatability 0.06992 0.4195 1.30
Reproducibility 1.53135 9.1881 28.52
Operator 0.00000 0.0000 0.00
Operator*Sample 1.53135 9.1881 28.52
Part-To-Part 5.14659 30.8795 95.84
Total Variation 5.37004 32.2202 100.00
为什么有两组Gage R&R计算,且其算出的结果不同?
Number of Distinct Categories = 4
本组值为4合理吗?
Gage R&R Study - ANOVA Method
Two-Way ANOVA Table With Interaction
Source DF SS MS F P
Sample 9 2208.84 245.426 34.86 0.000
Operator 2 0.83 0.417 0.06 0.943
Sample * Operator 18 126.72 7.040 1439.99 0.000
Repeatability 60 0.29 0.005
Total 89 2336.68
Gage R&R
%Contribution
Source VarComp (of VarComp)
Total Gage R&R 2.3499 8.15
Repeatability 0.0049 0.02
Reproducibility 2.3450 8.13
Operator 0.0000 0.00
Operator*Sample 2.3450 8.13
Part-To-Part 26.4874 91.85
Total Variation 28.8373 100.00
Study Var %Study Var
Source StdDev (SD) (6 * SD) (%SV)
Total Gage R&R 1.53294 9.1977 28.55
Repeatability 0.06992 0.4195 1.30
Reproducibility 1.53135 9.1881 28.52
Operator 0.00000 0.0000 0.00
Operator*Sample 1.53135 9.1881 28.52
Part-To-Part 5.14659 30.8795 95.84
Total Variation 5.37004 32.2202 100.00
为什么有两组Gage R&R计算,且其算出的结果不同?
Number of Distinct Categories = 4
本组值为4合理吗?
没有找到相关结果
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echozhou824 (威望:0)
赞同来自:
Sample 9 2208.84 245.426 34.86 0.000
Operator 2 0.83 0.417 0.06 0.943
Sample * Operator 18 126.72 7.040 1439.99 0.000
这里面的样本以及样本与操作员之间的交互作用P<=0.05,是否可以说明主要的变差来源于样本以及样本要操作员的交互作用? 该如何改进?